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X^2+X^2=42.25
We move all terms to the left:
X^2+X^2-(42.25)=0
We add all the numbers together, and all the variables
2X^2-42.25=0
a = 2; b = 0; c = -42.25;
Δ = b2-4ac
Δ = 02-4·2·(-42.25)
Δ = 338
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{338}=\sqrt{169*2}=\sqrt{169}*\sqrt{2}=13\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-13\sqrt{2}}{2*2}=\frac{0-13\sqrt{2}}{4} =-\frac{13\sqrt{2}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+13\sqrt{2}}{2*2}=\frac{0+13\sqrt{2}}{4} =\frac{13\sqrt{2}}{4} $
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